Integrand size = 38, antiderivative size = 240 \[ \int \frac {(d+e x)^{3/2} \left (15 d^2+20 d e x+8 e^2 x^2\right )}{\sqrt {a+b x}} \, dx=\frac {(b d-a e) \left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \sqrt {a+b x} \sqrt {d+e x}}{8 b^4}+\frac {\left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \sqrt {a+b x} (d+e x)^{3/2}}{12 b^3}+\frac {(17 b d-13 a e) \sqrt {a+b x} (d+e x)^{5/2}}{3 b^2}+\frac {2 e (a+b x)^{3/2} (d+e x)^{5/2}}{b^2}+\frac {(b d-a e)^2 \left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \text {arctanh}\left (\frac {\sqrt {e} \sqrt {a+b x}}{\sqrt {b} \sqrt {d+e x}}\right )}{8 b^{9/2} \sqrt {e}} \]
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Time = 0.15 (sec) , antiderivative size = 240, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {965, 81, 52, 65, 223, 212} \[ \int \frac {(d+e x)^{3/2} \left (15 d^2+20 d e x+8 e^2 x^2\right )}{\sqrt {a+b x}} \, dx=\frac {(b d-a e)^2 \left (35 a^2 e^2-90 a b d e+73 b^2 d^2\right ) \text {arctanh}\left (\frac {\sqrt {e} \sqrt {a+b x}}{\sqrt {b} \sqrt {d+e x}}\right )}{8 b^{9/2} \sqrt {e}}+\frac {\sqrt {a+b x} \sqrt {d+e x} (b d-a e) \left (35 a^2 e^2-90 a b d e+73 b^2 d^2\right )}{8 b^4}+\frac {\sqrt {a+b x} (d+e x)^{3/2} \left (35 a^2 e^2-90 a b d e+73 b^2 d^2\right )}{12 b^3}+\frac {2 e (a+b x)^{3/2} (d+e x)^{5/2}}{b^2}+\frac {\sqrt {a+b x} (d+e x)^{5/2} (17 b d-13 a e)}{3 b^2} \]
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Rule 52
Rule 65
Rule 81
Rule 212
Rule 223
Rule 965
Rubi steps \begin{align*} \text {integral}& = \frac {2 e (a+b x)^{3/2} (d+e x)^{5/2}}{b^2}+\frac {\int \frac {(d+e x)^{3/2} \left (4 e \left (15 b^2 d^2-3 a b d e-5 a^2 e^2\right )+4 b e^2 (17 b d-13 a e) x\right )}{\sqrt {a+b x}} \, dx}{4 b^2 e} \\ & = \frac {(17 b d-13 a e) \sqrt {a+b x} (d+e x)^{5/2}}{3 b^2}+\frac {2 e (a+b x)^{3/2} (d+e x)^{5/2}}{b^2}+\frac {\left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \int \frac {(d+e x)^{3/2}}{\sqrt {a+b x}} \, dx}{6 b^2} \\ & = \frac {\left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \sqrt {a+b x} (d+e x)^{3/2}}{12 b^3}+\frac {(17 b d-13 a e) \sqrt {a+b x} (d+e x)^{5/2}}{3 b^2}+\frac {2 e (a+b x)^{3/2} (d+e x)^{5/2}}{b^2}+\frac {\left ((b d-a e) \left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right )\right ) \int \frac {\sqrt {d+e x}}{\sqrt {a+b x}} \, dx}{8 b^3} \\ & = \frac {(b d-a e) \left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \sqrt {a+b x} \sqrt {d+e x}}{8 b^4}+\frac {\left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \sqrt {a+b x} (d+e x)^{3/2}}{12 b^3}+\frac {(17 b d-13 a e) \sqrt {a+b x} (d+e x)^{5/2}}{3 b^2}+\frac {2 e (a+b x)^{3/2} (d+e x)^{5/2}}{b^2}+\frac {\left ((b d-a e)^2 \left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right )\right ) \int \frac {1}{\sqrt {a+b x} \sqrt {d+e x}} \, dx}{16 b^4} \\ & = \frac {(b d-a e) \left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \sqrt {a+b x} \sqrt {d+e x}}{8 b^4}+\frac {\left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \sqrt {a+b x} (d+e x)^{3/2}}{12 b^3}+\frac {(17 b d-13 a e) \sqrt {a+b x} (d+e x)^{5/2}}{3 b^2}+\frac {2 e (a+b x)^{3/2} (d+e x)^{5/2}}{b^2}+\frac {\left ((b d-a e)^2 \left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right )\right ) \text {Subst}\left (\int \frac {1}{\sqrt {d-\frac {a e}{b}+\frac {e x^2}{b}}} \, dx,x,\sqrt {a+b x}\right )}{8 b^5} \\ & = \frac {(b d-a e) \left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \sqrt {a+b x} \sqrt {d+e x}}{8 b^4}+\frac {\left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \sqrt {a+b x} (d+e x)^{3/2}}{12 b^3}+\frac {(17 b d-13 a e) \sqrt {a+b x} (d+e x)^{5/2}}{3 b^2}+\frac {2 e (a+b x)^{3/2} (d+e x)^{5/2}}{b^2}+\frac {\left ((b d-a e)^2 \left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right )\right ) \text {Subst}\left (\int \frac {1}{1-\frac {e x^2}{b}} \, dx,x,\frac {\sqrt {a+b x}}{\sqrt {d+e x}}\right )}{8 b^5} \\ & = \frac {(b d-a e) \left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \sqrt {a+b x} \sqrt {d+e x}}{8 b^4}+\frac {\left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \sqrt {a+b x} (d+e x)^{3/2}}{12 b^3}+\frac {(17 b d-13 a e) \sqrt {a+b x} (d+e x)^{5/2}}{3 b^2}+\frac {2 e (a+b x)^{3/2} (d+e x)^{5/2}}{b^2}+\frac {(b d-a e)^2 \left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {a+b x}}{\sqrt {b} \sqrt {d+e x}}\right )}{8 b^{9/2} \sqrt {e}} \\ \end{align*}
Time = 0.46 (sec) , antiderivative size = 189, normalized size of antiderivative = 0.79 \[ \int \frac {(d+e x)^{3/2} \left (15 d^2+20 d e x+8 e^2 x^2\right )}{\sqrt {a+b x}} \, dx=\frac {\sqrt {a+b x} \sqrt {d+e x} \left (-105 a^3 e^3+5 a^2 b e^2 (89 d+14 e x)-a b^2 e \left (725 d^2+292 d e x+56 e^2 x^2\right )+b^3 \left (501 d^3+466 d^2 e x+232 d e^2 x^2+48 e^3 x^3\right )\right )}{24 b^4}+\frac {(b d-a e)^2 \left (73 b^2 d^2-90 a b d e+35 a^2 e^2\right ) \text {arctanh}\left (\frac {\sqrt {e} \sqrt {a+b x}}{\sqrt {b} \sqrt {d+e x}}\right )}{8 b^{9/2} \sqrt {e}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(570\) vs. \(2(204)=408\).
Time = 0.44 (sec) , antiderivative size = 571, normalized size of antiderivative = 2.38
method | result | size |
default | \(\frac {\sqrt {e x +d}\, \sqrt {b x +a}\, \left (96 b^{3} e^{3} x^{3} \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}-112 a \,b^{2} e^{3} x^{2} \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}+464 b^{3} d \,e^{2} x^{2} \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}+105 \ln \left (\frac {2 b e x +2 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}+a e +b d}{2 \sqrt {b e}}\right ) a^{4} e^{4}-480 \ln \left (\frac {2 b e x +2 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}+a e +b d}{2 \sqrt {b e}}\right ) a^{3} b d \,e^{3}+864 \ln \left (\frac {2 b e x +2 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}+a e +b d}{2 \sqrt {b e}}\right ) a^{2} b^{2} d^{2} e^{2}-708 \ln \left (\frac {2 b e x +2 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}+a e +b d}{2 \sqrt {b e}}\right ) a \,b^{3} d^{3} e +219 \ln \left (\frac {2 b e x +2 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}+a e +b d}{2 \sqrt {b e}}\right ) b^{4} d^{4}+140 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}\, a^{2} b \,e^{3} x -584 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}\, a \,b^{2} d \,e^{2} x +932 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}\, b^{3} d^{2} e x -210 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}\, a^{3} e^{3}+890 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}\, a^{2} b d \,e^{2}-1450 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}\, a \,b^{2} d^{2} e +1002 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}\, b^{3} d^{3}\right )}{48 b^{4} \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}}\) | \(571\) |
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Time = 0.42 (sec) , antiderivative size = 546, normalized size of antiderivative = 2.28 \[ \int \frac {(d+e x)^{3/2} \left (15 d^2+20 d e x+8 e^2 x^2\right )}{\sqrt {a+b x}} \, dx=\left [\frac {3 \, {\left (73 \, b^{4} d^{4} - 236 \, a b^{3} d^{3} e + 288 \, a^{2} b^{2} d^{2} e^{2} - 160 \, a^{3} b d e^{3} + 35 \, a^{4} e^{4}\right )} \sqrt {b e} \log \left (8 \, b^{2} e^{2} x^{2} + b^{2} d^{2} + 6 \, a b d e + a^{2} e^{2} + 4 \, {\left (2 \, b e x + b d + a e\right )} \sqrt {b e} \sqrt {b x + a} \sqrt {e x + d} + 8 \, {\left (b^{2} d e + a b e^{2}\right )} x\right ) + 4 \, {\left (48 \, b^{4} e^{4} x^{3} + 501 \, b^{4} d^{3} e - 725 \, a b^{3} d^{2} e^{2} + 445 \, a^{2} b^{2} d e^{3} - 105 \, a^{3} b e^{4} + 8 \, {\left (29 \, b^{4} d e^{3} - 7 \, a b^{3} e^{4}\right )} x^{2} + 2 \, {\left (233 \, b^{4} d^{2} e^{2} - 146 \, a b^{3} d e^{3} + 35 \, a^{2} b^{2} e^{4}\right )} x\right )} \sqrt {b x + a} \sqrt {e x + d}}{96 \, b^{5} e}, -\frac {3 \, {\left (73 \, b^{4} d^{4} - 236 \, a b^{3} d^{3} e + 288 \, a^{2} b^{2} d^{2} e^{2} - 160 \, a^{3} b d e^{3} + 35 \, a^{4} e^{4}\right )} \sqrt {-b e} \arctan \left (\frac {{\left (2 \, b e x + b d + a e\right )} \sqrt {-b e} \sqrt {b x + a} \sqrt {e x + d}}{2 \, {\left (b^{2} e^{2} x^{2} + a b d e + {\left (b^{2} d e + a b e^{2}\right )} x\right )}}\right ) - 2 \, {\left (48 \, b^{4} e^{4} x^{3} + 501 \, b^{4} d^{3} e - 725 \, a b^{3} d^{2} e^{2} + 445 \, a^{2} b^{2} d e^{3} - 105 \, a^{3} b e^{4} + 8 \, {\left (29 \, b^{4} d e^{3} - 7 \, a b^{3} e^{4}\right )} x^{2} + 2 \, {\left (233 \, b^{4} d^{2} e^{2} - 146 \, a b^{3} d e^{3} + 35 \, a^{2} b^{2} e^{4}\right )} x\right )} \sqrt {b x + a} \sqrt {e x + d}}{48 \, b^{5} e}\right ] \]
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\[ \int \frac {(d+e x)^{3/2} \left (15 d^2+20 d e x+8 e^2 x^2\right )}{\sqrt {a+b x}} \, dx=\int \frac {\left (d + e x\right )^{\frac {3}{2}} \cdot \left (15 d^{2} + 20 d e x + 8 e^{2} x^{2}\right )}{\sqrt {a + b x}}\, dx \]
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Exception generated. \[ \int \frac {(d+e x)^{3/2} \left (15 d^2+20 d e x+8 e^2 x^2\right )}{\sqrt {a+b x}} \, dx=\text {Exception raised: ValueError} \]
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Leaf count of result is larger than twice the leaf count of optimal. 739 vs. \(2 (204) = 408\).
Time = 0.37 (sec) , antiderivative size = 739, normalized size of antiderivative = 3.08 \[ \int \frac {(d+e x)^{3/2} \left (15 d^2+20 d e x+8 e^2 x^2\right )}{\sqrt {a+b x}} \, dx=-\frac {\frac {360 \, {\left (\frac {{\left (b^{2} d - a b e\right )} \log \left ({\left | -\sqrt {b e} \sqrt {b x + a} + \sqrt {b^{2} d + {\left (b x + a\right )} b e - a b e} \right |}\right )}{\sqrt {b e}} - \sqrt {b^{2} d + {\left (b x + a\right )} b e - a b e} \sqrt {b x + a}\right )} d^{3} {\left | b \right |}}{b^{2}} - \frac {28 \, {\left (\sqrt {b^{2} d + {\left (b x + a\right )} b e - a b e} \sqrt {b x + a} {\left (2 \, {\left (b x + a\right )} {\left (\frac {4 \, {\left (b x + a\right )}}{b^{2}} + \frac {b^{6} d e^{3} - 13 \, a b^{5} e^{4}}{b^{7} e^{4}}\right )} - \frac {3 \, {\left (b^{7} d^{2} e^{2} + 2 \, a b^{6} d e^{3} - 11 \, a^{2} b^{5} e^{4}\right )}}{b^{7} e^{4}}\right )} - \frac {3 \, {\left (b^{3} d^{3} + a b^{2} d^{2} e + 3 \, a^{2} b d e^{2} - 5 \, a^{3} e^{3}\right )} \log \left ({\left | -\sqrt {b e} \sqrt {b x + a} + \sqrt {b^{2} d + {\left (b x + a\right )} b e - a b e} \right |}\right )}{\sqrt {b e} b e^{2}}\right )} d e^{2} {\left | b \right |}}{b^{2}} - \frac {{\left (\sqrt {b^{2} d + {\left (b x + a\right )} b e - a b e} {\left (2 \, {\left (b x + a\right )} {\left (4 \, {\left (b x + a\right )} {\left (\frac {6 \, {\left (b x + a\right )}}{b^{3}} + \frac {b^{12} d e^{5} - 25 \, a b^{11} e^{6}}{b^{14} e^{6}}\right )} - \frac {5 \, b^{13} d^{2} e^{4} + 14 \, a b^{12} d e^{5} - 163 \, a^{2} b^{11} e^{6}}{b^{14} e^{6}}\right )} + \frac {3 \, {\left (5 \, b^{14} d^{3} e^{3} + 9 \, a b^{13} d^{2} e^{4} + 15 \, a^{2} b^{12} d e^{5} - 93 \, a^{3} b^{11} e^{6}\right )}}{b^{14} e^{6}}\right )} \sqrt {b x + a} + \frac {3 \, {\left (5 \, b^{4} d^{4} + 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} + 20 \, a^{3} b d e^{3} - 35 \, a^{4} e^{4}\right )} \log \left ({\left | -\sqrt {b e} \sqrt {b x + a} + \sqrt {b^{2} d + {\left (b x + a\right )} b e - a b e} \right |}\right )}{\sqrt {b e} b^{2} e^{3}}\right )} e^{3} {\left | b \right |}}{b^{2}} - \frac {210 \, {\left (\sqrt {b^{2} d + {\left (b x + a\right )} b e - a b e} {\left (2 \, b x + 2 \, a + \frac {b d e - 5 \, a e^{2}}{e^{2}}\right )} \sqrt {b x + a} + \frac {{\left (b^{3} d^{2} + 2 \, a b^{2} d e - 3 \, a^{2} b e^{2}\right )} \log \left ({\left | -\sqrt {b e} \sqrt {b x + a} + \sqrt {b^{2} d + {\left (b x + a\right )} b e - a b e} \right |}\right )}{\sqrt {b e} e}\right )} d^{2} e {\left | b \right |}}{b^{3}}}{24 \, b} \]
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Timed out. \[ \int \frac {(d+e x)^{3/2} \left (15 d^2+20 d e x+8 e^2 x^2\right )}{\sqrt {a+b x}} \, dx=\int \frac {{\left (d+e\,x\right )}^{3/2}\,\left (15\,d^2+20\,d\,e\,x+8\,e^2\,x^2\right )}{\sqrt {a+b\,x}} \,d x \]
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